A simplified method of determining the strain-ratio (R-value) in aluminum alloys
- PDF / 293,548 Bytes
- 3 Pages / 612 x 792 pts (letter) Page_size
- 3 Downloads / 303 Views
		    Feed Solution
 
 Crystals
 
 Analysis Sample No.
 
 Vol ml
 
 Cu, g/l
 
 51297 51283 51290 51304 composite*
 
 300 300 300 300 2250
 
 39.4 40.8 41.0 39.0 26.7
 
 Fe, H2SO 4, g/l g/l Wt, g 3.52 3.44 3.30 3.54 3.6
 
 Mother Liquor
 
 Analysis
 
 140.1 40.80 139.7 48.66 127.4 44.61 159.0 42.53 212.66
 
 Cu, Pct
 
 Fe, Pet
 
 Vol ml
 
 22.8 20.8 22.8 24.7 22.0
 
 0.40 74 0.34" 86 0.64 103 0.29 105 0.43 750
 
 Copper Product
 
 Analysis, Calculated
 
 Analysis
 
 Cu g]l
 
 Fe Pet
 
 Fe g/l
 
 15.4 10.0 19.6 8.8 20.5 8.8 21.5 8.8 12.0 9.2
 
 H2SO4 Wt, g/l g 568.0 488.0 372.4 318.0 -
 
 7.65 7.85 10.00 9.10 50.00
 
 0.001 0.001 0.06 0.06 0.02
 
 S Pet
 
 Copper Balance Mother Feed g
 
 0.20 11.80 0.15 12.25 0.68 12.30 0.25 11.70 0.12 60.00
 
 Copper Distribution Mother
 
 Crystals g
 
 Liquor g
 
 Feed Pet
 
 9.33 10.15 10.18 10.55 46.8
 
 1.11 1.68 2.12 2.26 9.0
 
 100 100 100 100 100
 
 Liquor Product Pet Pet 35.0 35.8 18.7 22.5 16.5
 
 65.0 64.2 81.3 77.5 83.5
 
 *There is some discrepancy in the material balance for copper. This is due to the fact that water of hydration in the crystals obtained was not constant, and varied on exposure to the air during handling.
 
 Table II. Analysis of Copper Produced. impurities E~pressed in ppm
 
 Sample No.
 
 Ag AI As Bi Ca Cd Co Cr Fe* Mg Mn Ni Pb S* Sb Si Sn Te Zn
 
 51297
 
 51283
 
 51290
 
 51304
 
 Composite
 
 nfl nf nfl nf nfl nfl nfl nfl
 
 nfl tr nfl nfl tr nfl nfl nfl
 
 10 tr n~ nfl tr nfl nf 600 tr nil 20 6900 20 50 nfl nfl nfl
 
 nfl nfl nfl n~ 600 10 10 nfl 5 0 50 5 tr nfl 10
 
 nil nfl nfl nfl 200 5 5 nf 2 1200 50 10 nfl nfl 10
 
 10
 
 10
 
 tr
 
 tr
 
 nfl nfl 2000 50 50 nfl nf nfl
 
 n~ nfl 1500 10 40 nfl nfl nf
 
 *By chemical methods.
 
 LOW grode Copper 0 x i d l Ore -
 
 the reduction would be used for making H2SO4 n e c e s s a r y for stripping the organic phase. The cost of evaporating the s t r i p solution to crystaP.ize CuSO 4 9nH20 could be the organic phase is added b e f o r e evaporation instead of adding it to the mother liquor. This is due to the d e c r e a s e d solubility of CuSO4 in the p r e s e n c e of HzSO4. For example, the solubility of CuSO4.5H20 e x p r e s s e d in g/100 g s a t u r a t e d solution is 18.47 in water and in a solution containing 50 g H2SO4/100 g s a t u r a t e d solution is 2.7. s The authors acknowledge with thanks the p e r m i s s i o n granted by The Anaconda Company to publish this work. 1. Gmelin: Handbuch derAnorganischen Chemie, vol. 60, Kupfer, part B, pp. 49899, Weinheim, Verlag Chemic, 1965. 2. Kim Vo Van and F. Habashi: Can. J. Chem., 1972, vol. 50, pp. 3872-75. 3. A Seidell and W. F. Linke: Solubilities oflnorganic andMetal-Organic Compounds, vol. 1, p. 970, Van Nostrand, New York, 1958.
 
 A Simplified Method of Determining the Strain-Ratio (R-Value) in Aluminum Alloys B. A. RIGGS
 
 H2SO 4
 
 6o804 IOlUtbon
 
 Looded
 
 BYdefinition the
 
 orgo.ir
 
 s t r a i n r a t i o is, [1]
 
 R 0 = ew/Et o,~on,e
 
 ~
 
 F*
 
 So 2
 
 Bleed
 
 u,.
 
 o . ,
 
 a
 
 .r
 
 powa*,
 
 HzS04
 
 I F i g . 1 - - P r o p o s e d f l o w s h e e t f o r t h e r e c o v e r y of p u r e c o p p e r f r o m l o w - g r a d e o r e b y H 2 - r e d u c t i o n of CuSO 4 .fiH20.		
Data Loading...
 
	 
	 
	 
	 
	 
	 
	 
	 
	 
	 
	