Answers to Practice Test
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Practice Test Answer: Chapter 1 (see. Fig. C.1)
Fig. C.1 Practice Test Answer to Chapter 1 Problem
T.J. Quirk, Excel 2010 for Engineering Statistics: A Guide to Solving Practical Problems, DOI 10.1007/978-3-319-02830-9_11, © Springer International Publishing Switzerland 2014
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Practice Test Answer: Chapter 2 (see. Fig. C.2) Fig. C.2 Practice Test Answer to Chapter 2 Problem
Appendix C: Answers to Practice Test
Appendix C: Answers to Practice Test
Practice Test Answer: Chapter 3 (see. Fig. C.3)
Fig. C.3 Practice Test Answer to Chapter 3 Problem
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Practice Test Answer: Chapter 4 (see. Fig. C.4)
Fig. C.4 Practice Test Answer to Chapter 4 Problem
Appendix C: Answers to Practice Test
Appendix C: Answers to Practice Test
Practice Test Answer: Chapter 5 (see. Fig. C.5)
Fig. C.5 Practice Test Answer to Chapter 5 Problem
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Practice Test Answer: Chapter 6 (see. Fig. C.6)
Fig. C.6 Practice Test Answer to Chapter 6 Problem
Appendix C: Answers to Practice Test
Appendix C: Answers to Practice Test
Practice Test Answer: Chapter 6 (continued) (d) a ¼ y-intercept ¼ 45.197 b ¼ slope ¼ ─ 6.394 (note the negative sign!) (e) Y ¼ a + b X Y ¼ 45.197 ─ 6.394 X (f) r ¼ correlation ¼ ─ .900 (note the negative sign!) (g) Y ¼ 45.197 ─ 6.394 (2.5) Y ¼ 45.197 ─ 15.985 Y ¼ 29.212 mpg (h) About 22 – 23 mpg
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Appendix C: Answers to Practice Test
Practice Test Answer: Chapter 7 (see. Fig. C.7)
Fig. C.7 Practice Test Answer to Chapter 7 Problem
Practice Test Answer: Chapter 7 (continued) 1. 2. 3. 4. 5. 6.
7. 8. 9. 10. 11.
Rxy ¼ .77 a ¼ y-intercept ¼ 0.29 b1 ¼ 1.01 b2 ¼ 0.01 Y ¼ a + b1 X1 + b2 X2 Y ¼ 0.29 + 1.01 X1 + 0.01 X2 Y ¼ 0.29 + 1.01 (3.8) + 0.01 (126) Y ¼ 0.29 + 3.84 + 1.26 Y ¼ 5.39 gallons + .76 + .60 + .65 The better predictor of TOTAL GALLONS USED was WEIGHT with a correlation of +.76. The two predictors combined predict TOTAL GALLONS USED only slightly better (Rxy ¼ .77) than the better single predictor by itself
Appendix C: Answers to Practice Test
Practice Test Answer: Chapter 8 (see Fig. C.8)
Fig. C.8 Practice Test Answer to Chapter 8 Problem
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Appendix C: Answers to Practice Test
Practice Test Answer: Chapter 8 (continued) Let STEEL ¼ Group 1, ALLOY A ¼ Group 2, and ALLOY B ¼ Group 3. (b) H0 : μ1 ¼ μ2 ¼ μ3 H1 : μ1 6¼ μ2 6¼ μ3 (f) MSb ¼ 105.25 and MSw ¼ 5.10 (g) F ¼ 20.63. (h) Mean of STEEL ¼ 84.83 and Mean of ALLOY A ¼ 79.38 (j) critical F ¼ 3.28 (k) Result: Since 20.63 is greater than 3.28, we reject the null hypothesis and accept the research hypothesis (l) Conclusion: There was a significant difference in strength between the three types of beams. (m) H0 : μ1 ¼ μ2 H1 : μ1 6¼ μ2 (n) df ¼ nTOTAL ─ k ¼ 36 ─ 3 ¼ 33 (o) 1/12 + 1/13 ¼ 0.08 + 0.08 ¼ 0.16 s.e ¼ SQRT (5.10 * 0.16) s.e. ¼ SQRT (0.82) s.e. ¼ 0.90 (p) ANOVA t ¼ (84.83 ─ 79.38) / 0.90 ¼ 6.06 (q) critical t ¼ 2.035 (r) Result: Since the absolute value of 6.06 is greater than the critical t of 2.035, we reject the null hypothesis and accept the research hypothesis (s) Conclusion: ALLOY A had significant
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